When A2+B2+C2=0, it implies A=B=C=0 (since the squares of real numbers are non-negative). Substitute the values of A,B, and C for determinant calculation into the matrix Calculation: |
1
cos0
cos0
cos0
1
cos0
cos0
cos0
1
| Since, Cos0=1 Thus Matrix becomes |
1
1
1
1
1
1
1
1
1
| Now determinant =1[(1×1−1×1)]−1[(1×1−1×1)]+1[(1×1−1×1)] ==1(0)−1(0)+1(0)=0 ∴ The value of the determinant is 0 .