Concept:The derivative of f(x) with respect to g(x) is g′(x)f′(x)​, provided both derivatives exist.Explanation:Let f(x)=ex and g(x)=xe.Compute f′(x)=dxd​ex=ex.Compute g′(x)=dxd​xe=exe−1.The required derivative is g′(x)f′(x)​=exe−1ex​.Multiply numerator and denominator by x: e⋅x⋅xe−1xex​=exexex​.Thus, the derivative is exexex​.Answer:exexex​ (Option A)