Test Index

UPSC NDA 2 2016 Mathematics Solved Paper

Show Para Hide Para

Consider the following for the next three (03) items that follow:

Let

f(x)=\begin{cases}-2, & -3 \leq x \leq 0\\ x-2, & 0 < x \leq 3\end{cases}

and

g(x)=f(|x|)+|f(x)|

[NDA II 2016]

© examsnet.com

Question : 89 of 120

Marks: +1, -0

What is the value of the differential coefficient of g(x) at

x=-2

$-1$
$0$
$1$
$2$

Solution:

For

x=-2

g(x)=-2+|-2|=-2+2

\Rightarrow g(x)=0

⇒ differential coefficient at

x=-2

is given as:

g'(x)=\lim\limits_{h\rightarrow0}\;\;\frac{g(x+h)-g(x)}{h}=\lim\limits_{h\rightarrow0}\;\;\frac{0-0}{4}=0

© examsnet.com

Go to Question:

Prev Question

Next Question