UPSC CDS Math Quadrilateral and Polygon Questions

Remember:The sum of exterior angles of any regular polygon of n (n ≥ 3) sides is 360°Therefore, sum of exterior angles of a regular polygon of m(m ≥ 3) sides = Sum of exterior angles of a regular polygon of n(n ≥ 3) sides = 360°Hence, statement 1 is incorrectRemember: Sum of the interior angles of a regular polygon of n sides$=(n-2)\times 180^{\circ}$Sum of the interior angles of a regular polygon of m sides$=(m-2)\times 180^{\circ}$For m > n ≥ 3$(m-2)\times 180^{\circ} > (n-2)\times 180^{\circ}$Therefore, the sum of the interiorangles of a regular polygon of m sides is greater than the sum of the interior angles of a regular polygon of n sides.Sum of the interior angles of a regular polygon of n sides + Sum of the interior angles of a regular polygon of m sidesHence, statement 2 is incorrect.