Concept:The HCF of two numbers of the form 2m−1 and 2n−1 is 2HCF(m,n)−1.Explanation:We need the HCF of 236−1 and 245−1.First, find the HCF of the exponents: 36 and 45.Prime factors: 36=22×32, 45=32×5.Common factors: 32=9. So HCF(36,45)=9.Now apply the formula: 2HCF(36,45)−1=29−1.Compute: 29=512, so 512−1=511.Answer:511