Concept:A polynomial that gives integer outputs for all integer inputs forces its coefficients to be integers when the leading coefficient is
1.
Explanation:Evaluate the polynomial
f(x)=x3+px2+qx+r at specific integer values.
At
x=0:
f(0)=r. Since
f(0) is an integer,
r must be an integer. So statement III is true.
At
x=1:
f(1)=1+p+q+r. This is an integer, and
r is integer, so
p+q is an integer.
At
x=−1:
f(−1)=−1+p−q+r. This is an integer, so
p−q is an integer.
Now evaluate at
x=2:
f(2)=8+4p+2q+r. This is an integer, so
4p+2q is an integer. Dividing by
2 gives
2p+q integer.
Subtract
p+q from
2p+q:
(2p+q)−(p+q)=p. Since both are integers,
p is an integer. Hence statement I is true.
Finally, from
p+q (integer) and
p (integer),
q=(p+q)−p is an integer. Hence statement II is true.
Thus all three statements are correct.
Answer:Option C: I, II and III