Given: m≡4(bmod12) n≡6(bmod12) Formula used: If a≡r1(bmodm) and b≡r2(bmodm), then: a±b≡r1±r2(bmodm) Calculations: Statement I: (m+n)bmod12 ⇒m+n≡4+6≡10(bmod12) The statement I is correct. Statement II: (m−n)bmod12 ⇒m−n≡4−6≡−2≡10(bmod12) The statement II is correct.