Concept:Factorisation using algebraic identities like a2−(b−c)2 and grouping.Explanation:Start with the expression: a2−b2−c2+2bc+a+b−c.Group the terms: a2−(b2+c2−2bc)+a+b−c.Recognise b2+c2−2bc=(b−c)2.So we have: a2−(b−c)2+a+b−c.Now factor a2−(b−c)2 as (a+(b−c))(a−(b−c))=(a+b−c)(a−b+c).The expression becomes: (a+b−c)(a−b+c)+(a+b−c).Factor out the common term (a+b−c): (a+b−c)[(a−b+c)+1]=(a+b−c)(a−b+c+1).Thus one factor is a−b+c+1.Answer:a−b+c+1