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UPSC CDS 2 2022 Math Paper

Consider the following for the next three (03) items that follow :

A frequency distribution table is given below :

x	0	1	2	3	4	5
f	46	p	q	25	10	5

Total frequency is 200 and mean of the distribution is

1.46

Question : 59 of 100

Marks: +1, -0

What is the value of

q

Solution: 👈: Video Solution

⇒ 46 + p + q + 25 + 10 + 5 = 200

⇒ p + q + 86 = 200

⇒ p + q = 114 -----(1)

Mean =

\left[\frac{p + 2q + 140}{200}\right]

⇒

\left[\frac{p + 2q + 140}{200}\right] = 1.46

(Mean = 1.46 given)

⇒

p + 2q = (292 - 140)

⇒

p + 2q = 152

-----(2)

Subtracting equation (1) from equation (2),

⇒

p + 2q - p - q = (152 - 114)

⇒

q = 38

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