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UPSC CDS 2 2022 Math Paper

Consider the following for the next three (03) items that follow :

A

triangle

{ABC}

with sides

{AB}=15 {cm}

{BC}=9 {cm}, {CA}=12 {cm}

is inscribed in a circle.

Question : 55 of 100

Marks: +1, -0

Solution: 👈: Video Solution

Hypotenuse

^{2}=

Base

^{2}+

Perpendicular

^{2}

We have,

AB=12\,\text{cm}, BC=9\,\text{cm}, AC=15\,\text{cm}

12^2+9^2=144+81=225=15^2

Hence,

\triangle ABC

is a right-angled triangle in which

\angle C=90^{\circ}

Using the above concept, the radius of the circle

OA=OB=OC=\frac{15}{2}=7.5\,\text{cm}

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