Given: The perimeter of the rhombus is 100m One of the diagonals is 40m Formula Used: Area of a triangle having sides a,b,c is A=√s(s−a)(s−b)(s−c) Where, S (semi perimeter )=(a+b+c)∕2 Concept Used: The sides of the rhombus are equal Calculation:
According to the question Sides of rhombus =100∕4=25m So, AB=25m,AD=25m , and BD=40m (given) S (semi perimeter )=(25+25+40)∕2=45m ⇒ Area of =√s(s−a)(s−b)(s−c) ⇒ Area of △ABD=√45×20×20×5 ⇒ Area of ∆ABD=300m2 So, The area of whole rhombus =300×2=600m2 ∴ The area of each part is 600÷4=150m2 .