Shortcut Trick Since the condition for α and β are not given So, we can take any value of α and β Let α=β=45∘ we can take 0∘ also but not 90∘ because tan90∘=∞ Now, On putting α=β=45∘ in the given equation, we get (sec245∘+tan45∘⋅tan45∘−tan245∘)2+(tan45∘−tan45∘)2−sec245∘⋅sec245∘ ⇒[(√2)2+1×1−1]2+(1−1)2−(√2)2×(√2)2 ⇒4+0−4=0 ∴ The required answer is 0 .