Given: Height of cylindrical tank=1m Diameter of tank=2m Radius of spherical droplet =1cm Formula used: Calculation: The volume of the cylinder =π(1)2×1 cubic meter Since 1 meter =100cm ⇒ The volume of the cylinder =π(100)2×100 The volume of spherical droplet =(4∕3)π×13 ⇒ The volume of spherical droplet =4π∕3 Therefore, 4π∕3cm3 volume decreases per second. Hence, Time required to empty tank = Volume of cylinder\/water discharge ⇒[π(100)2×100]∕(4π∕3) ⇒75×104sec ⇒75×104∕3600hr[∵1hr=3600sec] ⇒208.33≈210hr The tank will be emptied in approximately 210 hour: