GIVEN: 3 boys and 4 girls CONCEPT: Basic concept of Permutation and combination Number of ways to select ‘a’ out of ‘b’ =bCa CALCULATION: The group should have at least 2 boys. So, two cases are possible: 2 boys and 2 girls + 3 boys and 1 girl Required number of ways = 3C2×4C2+3C3×4C1 ⇒ 3 × 6 + 1 × 4 ⇒ 18 + 4 = 22