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UGC NET Paper 1 Exam 8 Dec 2023 Shift 1 Solved Paper

Question Numbers: 1-5

The following table shows the percentage of boys and difference between the number of boys and the number of girls among the students of six different schools A - F, who appeared in Board Examination during four different years from 2019 to 2022. Based on the data in the table, answer the questions that follow.

School Wise Details of Number of Students :

Year	2019	2020	2021	2022
School	Boys (%)	Difference (*)	Boys (%)	Difference (*)	Boys (%)	Difference (*)	Boys (%)	Difference (*)
A	70	136	60	70	75	184	60	86
B	40	84	48	18	45	48	60	90
C	44	60	55	24	60	52	56	24
D	44	84	57	84	55	72	65	192
E	75	280	60	136	70	264	66	224
F	44	90	56	96	65	228	45	84

Where Difference (*) means difference between number of boys and number of girls

Question : 5 of 50

Marks: +1, -0

What is the average number of children who appeared in the examination from school E, taking all the four years together?

Validate

Solution:

Concept:

The total number of students each year is found from the given difference between boys and girls, using the percentage of boys. Then the average over four years is calculated.

Explanation:

For 2019: Boys are 75%, so girls are 25%. The difference (75%−25%) = 50% equals 280. Hence, 100% = 280 × 2 = 560 students.

For 2020: Boys 60%, girls 40%. Difference 20% = 136. So 100% = 136 × 5 = 680 students.

For 2021: Boys 70%, girls 30%. Difference 40% = 264. So 100% = 264 × 2.5 = 660 students.

For 2022: Boys 66%, girls 34%. Difference 32% = 224. So 100% = 224 × 3.125 = 700 students.

Total students across all years = 560 + 680 + 660 + 700 = 2600.

Average =

2600 \div 4 = 650

Answer:

Option A: 650

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