The point of intersection of the lines 3x+4y+5=0 and 4x+y–2=0 is obtained by solving the two equations and we get x=1 and y=–2 Hence the point of intersection is (1, –2) Slope of the line
x
5
+
y
2
=1 is –2/5
x
5
+
y
2
=1 is
5
2
Required equation of a line passing through (1,−2) and having a slope of 5/2 is y−(−2)=(