TS ICET 2017 Solved Paper

Note : In a code the $10^{th}$ letter J of the English alphabet is coded as Z and for any k ≠ 10, the $k^{th}$ letter is coded as $r^{th}$ letter where r is the remainder when k + 2 is divided by 26. (For example, the $7^{th}$ letter G is coded as $11^{th}$ letter K since 5 × 7 + 2 = 37 leaves remainder 11 when divided by 26). The reverse process is used for decoding. Using these processes of coding and decoding answer Q. Nos. 56 to 60.