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TS ICET 19 Aug 2021 Shift 2 Paper

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In a certain code the alphabets A,B,C,…A, B, C, \ldots are given ranks 1,2,3,…1,2,3, \dots respectively, and then nthn^{\text{th}} letter is coded as kthk^{\text{th}} letter where 1≤k≤261 \le k \le 26 and 5n≡k(mod26)5n \equiv k \pmod{26}. For example, the 12th12^{\text{th}} letter LL is coded as the 8th8^{\text{th}} letter HH because 60≡8(60 \equiv 8( mod 26)). For decoding reverse process is followed. Based on this answer questions from 56 to 60
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