We have, x2+y2=16a2 and y2=6ax On solving both equations, we have ⇒‌‌x2+6ax−16a2=0 ⇒‌‌x2+8ax−2ax−16a2=0 ⇒‌‌x(x+8a)−2a(x+8a)=0 ⇒‌‌(x+8a)(x−2a)=0 ⇒‌‌x=−8a,2a
⇒‌‌x=2a‌‌[x≠−8a,‌ as ‌y2=6ax]
∴ Required area = Area of circle − Area of unshaded region