Normal vector to the plane 2x−y+z+1=0‌ is ‌2
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Given planes are perpendicular to the plane ( π ) ∴ Normal vector to the plane ( π ) is given by |
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|&=0
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−3
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−3
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‌=−3(0
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) Direction Ratio's of −3(0
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) is (0,1,1) Plane ( π ) is passing through the point ( 1,2,−3 ) ‌∴‌ Plane ‌(π)0(x−1)+1(y−2)+1(z+3)=0 ‌⇒‌‌y−2+z+3=0 ‌⇒‌‌0x+y+z+1=0 Given Plane (π)ax+by+cz+1=0 ∴‌‌a=0,b=1‌ and ‌c=1 Now, a2+b2+c2=02+12+12 =0+1+1=2
