TS EAMCET 9 May 2024 Shift 1 Solved Paper

Since, we can choose any face card (3 options) and any prime card (4 options) in a suit
⇒3×4=12 favourable combination in one suit.
∵ This situation can happen in any of the 4 suits
⇒12×4=48 overall favourable combination
and when drawing 2 cards from the same suit, then total possible ways
=‌13c2=78
Since, there are 4 suits, then total ways =78×4
Hence, required probability =‌

48

78×4

=‌

2

13