Given that there are 15 identical gold coins to be distributed among 3 persons. Also, each person gets at least 3 coins ⇒ total =3×3=9 coins ∴9 coins are already distributed in 1 ways. we now have 6 coins to be distributed between 3 people. ⇒x1+x2+x3=6,xi≥0 Number of Number of solutions is given by ‌n+r−1Cr−1 ‌⇒n=6,r=3 ∴ Reanired solution ∴ Required Number =‌6+3−1C3−1 =‌8C2=28