N=400 turns ‌A=10−2m2,I=0.5A ‌B=1T,θ=(90∘−60∘)=30∘ As we know, τ=NIBAsin‌θ τ‌=400×0.5×1×10−2×sin‌30∘ τ‌=400×0.5×10−2×‌
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τ‌=200×0.5×10−2 ‌=20×5×10−2=100×10−2 τ‌≅1N−m The initial moment of force acting on the coil in Nm is 1 .
