Initial temperature of wire, T1=303K Final temperature of wire, T2=356K Resistance increases \% = 10 \% Temperature coefficient α= ? Here, α=‌
(
∆R
R0
)
∆T
‌‌... (i) ∆R= change in resistance R= original resistance ∆T= change in temperature ∆T=T2−T1=356−303=53K from Eq. (i), ‌α=‌
0.10
53
=1.88×10−3C−1 ‌α≡2×10−3‌∘C−1 Thus, temperature coefficient of resistance of the material of the wire is approximately 2×10−3‌∘C−1.
