Given, ECu2+∕Cu0=0.34V so, ECu∘∕Cu2+=−0.34V At anode :Cu(s)⟶Cu2+(aq)+2e− At cathode :Cu2++2e−⟶Cu(s) Overall reaction: Cu(s)+Cu2+⟶Cu2++Cu(s) Using formula, E‌cell ‌∘=E‌red. ‌∘−E‌oxi. ‌0 Using Nernst equation, E‌cell ‌‌‌=E‌cell ‌∘−‌