×(−6)]=(1,3) C2= Centre of second circle =[−‌
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×(−8),−‌
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×(2)]=(4,−1) r1= radius of first circle =√1+9−10+r2=|r| r2= radius of second circle =√16+1−8=3 According to the question, |r2−r1|<c1c2<r2+r1 |3−|r||<5<3+|r| where, C1C2=√(4−1)2+(−1−3)2=5 ‌‌={