For the reaction {H}₂(g)+{I}₂(g)leftharpoons2{HI}(g)

Correct Answer is : Kp=Kc≠0K_p = K_c ≠ 0Kp=Kc=0

Correct Answer is : Kp=Kc≠0K_p = K_c ≠ 0Kp=Kc=0

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TS EAMCET 6-Aug-2021 Shift 1 Question Paper

Section: Chemistry

Question : 133 of 160

Marks: +1, -0

For the reaction

\mathrm{H}_2(g)+\mathrm{I}_2(g)\rightleftharpoons2\mathrm{HI}(g)

Solution:

\mathrm{H}_2(g)+\mathrm{I}_2(g)\rightleftharpoons2\mathrm{HI}(g)

For

K_p

we use partial pressure of each gaseous species and

K_p

expression is written as,

K_p = \frac{[\mathrm{HI}]^2}{[\mathrm{H}_2][\mathrm{I}_2]}

Relationship between

K_p

and

K_c

K_p = K_C (RT)^{\Delta n}

\Delta n = \; \text{ Moles of gaseous products - moles of gaseous } \;

\; \text{ reactants } \;

\Delta n = 2 - 2 = 0 \Rightarrow K_p = K_C (RT)^0

K_p = K_C \Rightarrow K_C = \; \frac{[\mathrm{HI}]^2}{[\mathrm{H}_2][\mathrm{I}_2]}

\therefore \; \; K_p = K_C \neq 0

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