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TS EAMCET 5 May 2018 Shift 2 Solved Paper

Section: Mathematics

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Question : 80 of 160

Marks: +1, -0

The general solution of the differential equation,

is

y=loge(
x+y+2
k
)
x=loge(
x+y+2
k
)
x=cey+y+2
y=cex+x+2

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