Given, equation of distance x(t)=αt+βt3. . . (i) where, α=2m∕s and β=0.01m∕s3. Initial time, t1=2s and final time, t2=4s As we know that, Average velocity (vav)=‌
‌ Total displacement ‌(x)
‌ Total time ‌(t)
Since ‌‌x(t)=αt+βt3 ∴ Distance travelled by car in time interval (t2−t1) will be x‌‌=α(t2−t1)+β(t23−t13) ‌‌=2(4−2)+‌