Given, plane 2x−2y+4z+5=0 Direction ratios of the normal =2,−2,4 Equation of line passing through (1,23,2) and dr's 2, −2,4 is given by 2x−1=−2y−23=4z−2=rx=2r+1,y=−2r+23,z=4r+2 This point also lies on given plane. ∴2(2r+1)−2(−2r+23)+4(4r+2+5=024r+12=0 or r=2−1∴ Required point (2⋅(2−1)+1,−2(2−1)+23,4(2−1)+2)=(0,25,0)