Given, Radius of loop, r=10cm=10×10−2m Total charge on loop, q=10−5C Small arc length, x=3.14×10−6m Let, E be the electric field. As we know that, E=‌
kq′
r2
. . . (i) where, k= Coulomb's constant and q′= charge on arc length x. ∴‌‌q′‌‌=‌
q
2Ï€r
x ‌‌=‌
10−5
2π×10×10−2
×314×10−6=‌
1
2
×10−10C Substituting in Eq. (i), we get E‌‌=‌