On comparing corresponding components, 7+3β‌=5α+3 ⇒‌‌3β‌=5α−4....(i) −3‌=5+6β+3γ ⇒‌‌3γ=−8−6β ⇒‌‌3γ=−10α.....(ii) 3α+3γ=−5+3β+9 ‌3α+3γ=−5+3β+9 ⇒‌‌3α=4+3β−3γ ....(iii) On putting the values from Eqs. (i) and (ii) into Eq. (iii), we get ‌3α=4+(5α−4)−(−10α) ⇒‌‌3α=5α+10α ⇒‌‌α=0 From Eq. (i), 3β=0−4 ⇒‌‌β=‌