Given, word is TSEAMCET In the word, T and E occur twice. So, we have S, A, M, C, TT, EE. We have 6 distinct letter. Way 1 4 letters selected and all are distinct. ‌6C4=‌6C2=‌
6×5
2×1
=15 Way 2 2 letters are alike and 2 are distinct ‌2C1×‌5C2=2×‌
5×4
2×1
=20 Way 3 2 letters are alike and rest 2 are also alike ‌2C2=1 So, the total number of ways =15+20+1=36