Given, density of water, ρw=1000kg∕m3 Specific heat capacity of water, sw=400Jkg−1K−1 Volume of water, V=31=3×10−3m3 ∴ Mass of water, m=V×ρw =3×10−3×1000=3kg Change of temperature of water, ∆T=[(273+80)−(273+0)]K =80K Heat required, Q=msw∆T =3×42.00×80=1008000 =1.008×106J Heat produced by heater, H=