) ⇒‌‌1=α+β+2γ......(i) −2=α+2β−γ......(ii) 5=α+3β+γ.......(iii) From Eqs. (i) and (ii), we get −β+3γ=3 .....(iv) From Eqs. (ii) and (iii), we get β+2γ=7 ......(v) From Eqs. (iv) and (v), we get ‌γ=2,‌ and ‌β=3 ‌α=−6 ‌α2−β2+γ2=36−9+4=31