1‌cm=107‌nm Edge length of original cube =107‌nm Volume of original cube (V)=(107)3‌nm Edge length of new cube =1‌nm Volume of new cube =(1)3‌nm If the number of new cubes formed is n , then volume of total new cubes will be (V1)=n×(1)3‌nm But V=V1 ∴‌‌(107)3=n×(1)3 ∴‌‌n=1021 The surface area of the original cube (S)=6×(107)2nm2=6×a2 The surface area of the total cubes formed after crushing the original cube ‌=(S1)=6×1021×(1)2nm2 ‌