)11 ‌‌Tr+1=‌11Crar⋅b11−rx3r−22 ‌ For ‌x−7 ‌‌3r−22=−7 ⇒‌‌r=5 ‌‌L=‌ Coefficient of ‌x−7=‌11C5a5b6 ‌ General term of ‌(bx2+‌
a
x
)11 ‌‌Tr+1=‌11Cra11−rbrx3r−11 For x7 3r−11=7 ⇒‌‌r=6 M=‌ Coefficient of ‌x7=‌11C6a5b6 L+M=(‌11C5+‌11C6)a5b6 =‌12C6a5b6 Now, coefficient of x6 in (ax2+‌