(*) Given, mass of solid cylinder, M=10kg Radius, R=40cm=0.4m L=9R=9×0.4=36m Moment of inertia of the solid cylinder about the line passing through its centre and perpendicular to its axis is given as
ICOM‌‌=M[‌
L2
12
+‌
R2
4
]=10[‌
(36)2
12
+‌
(0.4)2
4
] ‌‌=10[1.08+0.04]=10×112 ⇒ICOM=11.2kg−m2 According to parallel axis theorem, moment of inertia of cylinder about aline passing through its edge and perpendicular to its axis is given as I′‌‌=ICOM+M(‌