Current gain of a transistor =0.98 Since it is less than 1, so it is the current gain in common base configuration i.e., α=0.98 So, current gain in common emitter configuration,
β=‌
α
1−α
=‌
0.98
1−0.98
=‌
0.98
0.02
=49
Now, ‌‌β=‌
∆IC
∆IB
where, ∆IC= change in collector current = ? and ∆IB= change in base current =0.5mA On putting the values, we get