The position of the particle is given as y(t)=10te−2t Velocity of the particle is given as v‌‌=‌
d
dt
y(t)=‌
d
dt
(10te−2t) ‌‌=10[te−2t(−2)+e−2t⋅1] ‌‌=10[−2te−2t+e−2t]=10e−2t(1−2f) When body stops, then [v=0⇒e−2t(1−2f)=0⇒1−2t=0 t=‌
1
2
s From Eq. (i), displacement of the particle from origin is given as y(‌