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TS EAMCET 04 May 2019 Shift 2 Solved Paper

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Question : 74

Total: 160

∫ cosec5 x dx =

cosecxcot3x
4
−
5
8
cosecxcotx+
3
8
log|tan
x
2
|+c
-
cosecxcot3x
4
−
5
8
cosecxcotx+
3
8
log|tan
x
2
|+c
-
cosec3xcotx
4
−
3
8
cosecxcotx+
3
8
log|tan
x
2
|+c
-
cosec3xcotx
4
+
3
8
cosecxcotx−
3
8
log|tan
x
2
|+c

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