The concentration in M of {OH}^{- } in 0.001 M {H₂SO₄ is

Correct Answer is : 5 × 10−1210^{-12}10−12

Correct Answer is : 5 × 10−1210^{-12}10−12

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TS EAMCET 04 May 2019 Shift 2 Solved Paper

Section: Chemistry

Question : 133 of 160

Marks: +1, -0

\mathrm{OH}^{- }

\mathrm{H_2SO_4}

Solution:

Consider the reaction shown below,

\mathrm{H}_{2}\mathrm{SO}_{4} \rightleftharpoons 2 \mathrm{H}^{+}+ \mathrm{SO}_{4}^{2-}

The concentration of

\mathrm{H}^{+}

is calculated as

\mathrm{H}^{+} \;\; =2 \times 0.001 \mathrm{M}

\;\; =0.002 \mathrm{M}

The pH is calculated as,

\mathrm{pH} \;\; =-\log [\mathrm{H}^{+}]

\;\; =-\log (0.002)

\;\; =2.69

The

\mathrm{pOH}

is calculated as

\mathrm{pH} + \mathrm{pOH} =14

\mathrm{pOH} =14- \mathrm{pH}

\mathrm{pOH} =14-2.69

\mathrm{pOH} =11.31

The

[ \mathrm{OH} ]

concentration is calculated as,

\mathrm{pOH} \;\; =-\log [ \mathrm{OH}^{-}]

11.31 \;\; =-\log [ \mathrm{OH}^{-}]

[ \mathrm{OH}^{-}] \;\; =5 \times 10^{-12}

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