The rate of the equations is given as, Rate(r)=k[‌ conc. ‌]n Here, the order of the reaction is n The rate of reaction is, ‌
−d[NO]
dt
=[NO]x[H2]y Substitute the given values. 43.2×10−5=[3×10−2]x[1×10−3]y......(i) 4.8×10−5=[1×10−2]x[1×10−3]y........(ii) On dividing the value of equation (i) by (ii) we get, x=2 Hence, the order of [NO] is 2 Similarly for set ii and iii. ‌
86.4×10−5
43.2×10−5
=[‌
2×10−3
1×10−3
]y y=1 Hence, the order of [H2] is 1 Thus, the rate of reaction becomes, ‌