TGTET Paper 1 Exam 23 Jul 2017 Paper

Concept:To find the remaining part of a whole task, we first calculate the total part completed and then subtract it from the whole (which is considered as 1 unit).Explanation:Pranava completed a part of his homework on Saturday and another part on Sunday. We need to find out how much homework is still left.1. First, let's find the total fraction of homework Pranava finished on both days. Homework finished on Saturday = $\frac{5}{12}$ Homework finished on Sunday = $\frac{1}{4}$2. To add these fractions, we need a common denominator. The least common multiple (LCM) of 12 and 4 is 12. So, we convert $\frac{1}{4}$ to an equivalent fraction with a denominator of 12: $\frac{1}{4} = \frac{1 \times 3}{4 \times 3} = \frac{3}{12}$3. Now, add the fractions of homework finished: Total homework finished = $\frac{5}{12} + \frac{3}{12} = \frac{5+3}{12} = \frac{8}{12}$4. The total homework is considered as 1 whole unit. To find the homework left, we subtract the total homework finished from 1. Homework left = $1 - \frac{8}{12}$5. To subtract, we write 1 as $\frac{12}{12}$. Homework left = $\frac{12}{12} - \frac{8}{12} = \frac{12-8}{12} = \frac{4}{12}$6. Finally, we simplify the fraction $\frac{4}{12}$ by dividing both the numerator and the denominator by their greatest common divisor, which is 4. Homework left = $\frac{4 \div 4}{12 \div 4} = \frac{1}{3}$So, $\frac{1}{3}$ part of the homework is left.Answer:$\frac{1}{3}$