TG EAMCET 3 May 2025 Shift 2 Paper

The problem asks for the approximate difference between the temperature of maximum density of heavy water $(\mathrm{D}_2\mathrm{O})$ and ordinary water $(\mathrm{H}_2\mathrm{O})$.The temperature of maximum density of $\mathrm{H}_2\mathrm{O}$ is approximately $3.98^{\circ}\mathrm{C}$.The temperature of maximum density of $\mathrm{D}_2\mathrm{O}$ is approximately $11.2^{\circ}\mathrm{C}$.The difference in temperature in Celsius is$\Delta T_C=11.2^{\circ}\mathrm{C}-3.98^{\circ}\mathrm{C}=7.22^{\circ}\mathrm{C}$The problem specifies the temperatures in Kelvin, with $y$ being the temperature for $\mathrm{H}_2\mathrm{O}$ and $x$ for $\mathrm{D}_2\mathrm{O}$. The difference is $(x-y)$ in Kelvin.The magnitude of a temperature difference is the same whether measured in Celsius or Kelvin.$\Delta T_K=\Delta T_C$So, the difference in Kelvin is 7.22 K . The value 7.22 K is closest to the option 7.0 K .