Given equation is ax2+ay2+2gx+2fy−2=0 Put(−1,0)into this equation, we get ‌a(−1)2+a(0)2+2g(−1)+2f(0)−2=0....(i) ‌⇒‌‌a−2g−2=0 Put(−1,1), we get ‌a(−1)2+a(1)2+2g(−1)+2f(1)−2=0 ‌⇒‌‌a+a−2g+2f−2=0 ‌⇒‌‌2a−2g+2f−2=0 ‌⇒‌‌a−g+f−1=0....(ii) Put(1,1), we get ‌a(1)2+a(1)2+2g(1)+2f(1)−2=0 ‌⇒‌‌a+g+f−1=0....(iii) Subtract Eq. (ii) from Eq. (iii), ‌(a+g+f−1)−(a−g+f−1)=0 ‌⇒‌‌2g=0 ‌⇒‌‌g=0 Putg=0into Eq. (i), we get ‌a−2(0)−2=0 ⇒ ⇒a=2