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Telangana TET Paper 2 Math and Science Model Paper 2

Section: Math and Science

Question : 127 of 150

Marks: +1, -0

\sqrt{14.44}+\sqrt{(9+x^{2})}

= 8.8, then find the value of x.

Solution:

Concept:

The equation involves square roots. Isolate the square root term, then square both sides to remove the root.

Explanation:

First, find

\sqrt{14.44}

. Since

38^2 = 1444

, we have

\sqrt{14.44} = 3.8

Substitute into the equation:

3.8 + \sqrt{9 + x^2} = 8.8

Subtract 3.8 from both sides:

\sqrt{9 + x^2} = 5

Square both sides:

9 + x^2 = 25

Subtract 9:

x^2 = 16

Take square root:

x = 4

x = -4

. Since the options only give positive values,

x = 4

Answer:

Option B: 4

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