Symbiosis National Aptitude Test SNAP 2019 Paper

Let the speed of two trains are A m/sec. and B m/sec.
(here A > B)
Now, when moving in opposite direction, then
(A + B) × 20 = 150 + 150
(A + B) =

300

20

⇒ A + B = 15 ...(i)
when moving in same direction, then
(A – B) × 40 = 150 + 150
(A – B) =

300

40

= 7.5
From (i) and (ii), we get that
A =

15+7.5

2

= 11.25 m/sec.
Hence, speed of faster train = 11.25 m/sec.