V1=2000V,V2=250V,R1=1.15Ω,R2=0.0155Ω From equation(1) K=
V2
V1
K=
250
2000
K=
1
8
Effective resistance of the transformer as referred to the secondary of the transformer. From equations (2) & (3) R02=0.0155+
1.15
82
R02=0.0335Ω Power output P=40kVA V2I2=40×103 I2=
40000
250
I2=160A=Ifl V2I2=40×103 I2=
40000
250
I2=160A=Ifl Ifl is the full load current flowing through the secondary. We required to find power loss at half full load condition So, current at half full load is given as, Ihfl=
160
2
=80A ∴ Total power loss at half full load condition is given as, Phfl=Ihfl2×R02 Phfl=802×0.0335 Phfl=214.2W