Output power rating of single phase Induction motor = 2 HP = 2 × 746 W = 1492 W. Supply voltage (V) = 240 V Efficiency (η) = 70 % = 0.7 Power factor (cos ϕ) = 0.8 η=
Output power
Input power
Input Power (P)=
Output power
η
=
1492
0.7
=2131.43W Now P=V×I×cos‌ϕ 2131.43=240×I×0.8 I=11.1A So our closest possible answer is 10.95 A.